profit and loss mcq pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024

Answer: (c)

According to question,

SP 250 + 300 = 550

Thus, Remaining parts sold at CP

SP of 3/5th part = $3/5$ × 360000

= Rs. 216000

Answer: (c)

According to question,

CP of 12 articles = Rs. P

SP of article = Rs. $P/8$ × 12 = $3/2$ P

Profit = SP - CP

= $({3P}/2 - P) = {3P - 2P}/2 = P/2$

Profit% = $P/{2/P} × 100 = 1/2 × 100$

= 50%

Answer: (c)

According to question,

$10 ⇄↖{cut 10%}↙{increase 1 unit} 9$

Raised % = $1/9 × 100 = 11{1}/9%$

Answer: (c)

Single discount % will be

10% = $-1/10$

10% = $1/10$ → Discount (-1) 9

20% = $1/5$ → Discount (-1) 4

25% = $1/4$ → $4/50$ (23 Discount) $3/27$

Discount % = $\text"Discount"/\text"MRP"$ × 100

= $23/50$ × 100% = 46%

Alternative: From first two successive discounts using 10% and 20%

→ Equal single discount

= $(a + b - {ab}/100)$%

$(10 + 20 - {10 × 20}/100)%$ = 30 - 2

= 28 %

Using 28% and last successive discount of 25%

= $(25 + 28 - {25 × 28}/100)%$

Final equal discount = 46%

Answer: (a)

CP (100)

↓ +40%

MP (140)

↓ Discount 20%

SP (112)

Let CP be 100

12 units → Rs. 48

1 unit → Rs. 4

100 units → 4 × 100

= Rs. 400